**after multiplying the reaction by a factor of 2, what is the new equilibrium equation?** This is a topic that many people are looking for. **amritsang.org** is a channel providing useful information about learning, life, digital marketing and online courses …. it will help you have an overview and solid multi-faceted knowledge . Today, ** amritsang.org ** would like to introduce to you **7.1 What Happens to Kc When the Equilibrium Equation Coefficients are Changed? [SL IB Chemistry]**. Following along are instructions in the video below:

Dont know lets work it out so fyi that is the production of of sulfur trioxide. Which is used to make sulfuric acid and my equilibrium concentrations are there one molar 2 molar. 4 molar now those are going to stay the same theyre independent of any messing about i do with the equations coefficients those are unchanging.

So let me write out the equilibrium constant expression kc and put in my equilibrium concentrations oh thats nice and that gives me 8 again im ignoring the units for clarity on this video so if i change the coefficients in the equilibrium equation is that gonna change my value for kc so let me adjust kc to reflect the new reality and put the numbers back in oh look at that its different so messing with the coefficients does change the value of kc in fact. I haft the coefficients and kc became the square root of what it was before the square root of eight is two point eight. Now.

Theres some sort of relationship.

There so if you have the coefficients kc is raised to the power half. Lets see if that was just a fluke so let me double the coefficients now from what they were originally put in my numbers. Again and remember one two and four molar.

They are unchanging thats the equilibrium concentrations and kc is now sixty four okay. So if you double the coefficients kc is raised to the power 2. So that seems to be the relationship and if you triple the coefficients.

Then youre going to raise kc to the power.

3. Let me just zoom in on that table bit all righty. So what if an is reversed.

Well. This is the classic contact process again let me write out the equation for kc. I lets say the values.

8 over 1 now if i reverse the equilibrium like so well.

Im gonna have to invert kc and actually the value for k c. Is also inverted so its now 1 8. So reversing an equilibrium or reversing an equation inverts kc and finally what if you have a sequence of equilibria.

What happens to kc then overall well let me add up these two equations to get my final equilibrium equation and what happens to kc you multiply them so 500 so if you add equations youre gonna have to multiply the kcs together and im assuming everythings a gas thats what the g means so in summary. Raise kc whatever the coefficients have been x. If you reverse the equation you need to invert kc.

And if youre adding equilibria multiply. The kc values together and were done. .

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